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When $a \ne 0$, there are two solutions to \( ax^2 + bx + c = 0 \) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

// gallery post: 
title: 文章排版
date: 2017-11-10 23:30:04
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MathJax

When $a \ne 0$, there are two solutions to \( ax^2 + bx + c = 0 \) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$